2014年11月12日 星期三

2014.10.22 數學機經分享#341 (未完)

A sum of $200,000 from a certain estate was divided among a spouse and three
children. How much did the youngest child receive?

(1) The spouse received 1/2 of the sum from the estate, and the oldest child
received 1/4 of the reminder

(2) Each of the two younger children received 12,500 more than the oldest
child and 62500 less than the spouse

[解]假設母親拿A,三個孩子(由大到小)分別拿B, C, D,
       可以得到 A + B + C + D = 200,000。題幹欲判斷D值是否能求出。

(1)A=200,000*(1/2)=100,000,
   B=100,000*(1/4)=25,000,
     以上代入原式,
     得到 100,000 + 25,000 + C + D = 200,000,
  無法解出 C 與 D,
  條件不充分;

(2)由條件可知,C = D = A - 62,500 = B + 12,500,
     將四人都以C表示,
  得到: A + B + C + D = ( C + 62,500 ) + ( C - 12,500 ) + C + C = 200,000,
     C可以求出,D也可以求出。
  條件充分;

選B。